0=60+36x+4.9x^2

Solution for 0=60+36x+4.9x^2 equation:

0=60+36x+4.9x^2

We move all terms to the left:

0-(60+36x+4.9x^2)=0

We add all the numbers together, and all the variables

-(60+36x+4.9x^2)=0

We get rid of parentheses

-4.9x^2-36x-60=0

a = -4.9; b = -36; c = -60;
Δ = b2-4ac
Δ = -362-4·(-4.9)·(-60)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{30}}{2*-4.9}=\frac{36-2\sqrt{30}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{30}}{2*-4.9}=\frac{36+2\sqrt{30}}{-9.8}
$